Navigasi Materi

geogebra2

GeoGebra - Protokol Konstruksi

hiperbola

Nama Definisi Nilai
Angka a   a = -0.8
Angka b   b = -3.8
Angka c   c = 0.1
Angka d   d = 1.9
Plane p a x + b y + c z + d = 0 p: -0.8x - 3.8y + 0.1z = -1.9
Titik A Titik(Sumbuz) A = (0, 0, 4)
Titik B Perpotongan(Sumbuz, SumbuX) B = (0, 0, 0)
Cone e Kerucut(A, B, 2) e: 16.76
Surface g Kerucut(A, B, 2) g: 28.1
Lingkaran f Kerucut(A, B, 2) f: X = (0, 0, 4) + (2 cos(t), 2 sin(t), 0)
Titik C Titik(Sumbuz) C = (0, 0, -4)
Cone h Kerucut(C, B, 2) h: 16.76
Surface i Kerucut(C, B, 2) i: 28.1
Lingkaran k Kerucut(C, B, 2) k: X = (0, 0, -4) + (2 cos(t), -2 sin(t), 0)
Hiperbola q SegmenPerpotongan(p, e) q: X = (0.1, 0.48, 0.05) + ( 0.01 cosh(t) - 0.48 sinh(t),  0.02 cosh(t) + 0.1 sinh(t),  0.98 cosh(t))
Titik D Pojok(q) D = (1.99, 0.19, 4)
Titik E Pojok(q) E = (-1.75, 0.97, 4)
Titik F Pojok(q) F = (?, ?, ?)
Titik G Pojok(q) G = (?, ?, ?)
Hiperbola r SegmenPerpotongan(p, h) r: X = (0.1, 0.48, 0.05) + ( 0.01 cosh(t) - 0.48 sinh(t),  0.02 cosh(t) + 0.1 sinh(t),  0.98 cosh(t))
Titik H Pojok(r) H = (4.47; 156.98 ; -63.43 )
Titik I Pojok(r) I = (2, -0.03, -4)
Teks teks1   "Irisan Kerucut berbentuk hiperbola"
Titik J Pojok(r) J = (?, ?, ?)
Titik K Pojok(r) K = (?, ?, ?)
Row Input Output
#1
Created with GeoGebra